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## Homework Statement

The original problem with statement is http://images3a.snapfish.com/232323232fp733;9>nu=52::>379>256>WSNRCG=335:728:;4347nu0mrj".

## Homework Equations

Newton's Laws 1-3

## The Attempt at a Solution

Note that the table is frictionless, the only friction is between the two boxes

So first:

[tex] \mu = .45 [/tex]

and the T on M1 is

[tex] T_{m_{1}}=F_{a} [/tex]

and T on M2 is

[tex] T_{m_{2}}=-F_{a} [/tex]

and

[tex] F_{n_{1}}=m_{1}g [/tex]

[tex] F_{n_{2}}=m_{1}g+m_{2}g [/tex]

So the friction force on M1 from M2 should be:

[tex] F_{ \mu_{1}} = \mu F_{n_{1}} [/tex]

and the friction on M2 from M1 should be:

[tex] F_{ \mu_{2}}=\mu F_{n_{1}} [/tex]

So i am kind of confused as to how I should use the T forces... here is what I did:

[tex] F_{net_{x}} = F_{a}+F_{\mu_{1}-T-F_{\mu_{2}}=0 [/tex]

[tex] F_{net_{y}}=F_{n_{1}}+F_{n_{2}}-m_{1}g-m_{2}g=0 [/tex]

is that right? I am not sure how to set up T because for m1 t is opposite the friction force and for m2 T is opposite the Fa force... should I set up a relationship that way to do this correctly?

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