Forming a formula from a-b=c-d

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The equation a-b=c-d can be rearranged to solve for c, resulting in c=a-b+d, which is correct. The alternative equation c=a/b*d is incorrect and likely stems from a misunderstanding of the original relationship. The only valid transformations of the equation yield variations of c=a-b+d, with different arrangements of the terms. There are six equivalent forms to express c based on the initial equation. Clarity in notation is essential to avoid confusion between subtraction and division.
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Hi, I am beginner in mathematics , I have the following relationship:

a-b=c-d

I need to calculate c under the assumption that a, b and d are known values.
I got c=a-b+d
and c=a/b*d

can I use any other formulas?!
 
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khazaymeh said:
Hi, I am beginner in mathematics , I have the following relationship:

a-b=c-d

I need to calculate c under the assumption that a, b and d are known values.
I got c=a-b+d
and c=a/b*d

can I use any other formulas?!

c=a-b+d follows directly from the stated relationship. Where did you get c=a/b*d ?
 
khazaymeh said:
Hi, I am beginner in mathematics , I have the following relationship:

a-b=c-d

I need to calculate c under the assumption that a, b and d are known values.
I got c=a-b+d
What you got above is correct. To solve for c, add d to both sides of the equation.

I don't know how you got the equation below, but it's incorrect.
khazaymeh said:
and c=a/b*d

can I use any other formulas?!
The equation you started with is very simple, so the only possible differences are how the three terms on the other side are arranged, with a total of six ways.

c = a - b + d
c = a + d - b
c = d + a - b
c = d - b + a
c = -b + a + d
c = -b + d + a
 
khazaymeh said:
Hi, I am beginner in mathematics , I have the following relationship:

a-b=c-d

I need to calculate c under the assumption that a, b and d are known values.
I got c=a-b+d
and c=a/b*d

can I use any other formulas?!

c=a-b+d follows from a-b=c-d

c=a/b*d follows from a/b=c/d

Did you write it down in a way that your -'s look like /'s ?
 
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