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Formula for average current on a coil inside a solenoid

  1. Jul 13, 2012 #1
    1. The problem statement, all variables and given/known data
    A solenoid of length 20.0 cm is made of 5000 circular coils. It carries a steady current of 10.0 A. Near its center is places a very flat and small coil with a resistance of 2.50 Ω made of 100 circular loops, each with a radius of 3.00 mm. This small coil is oriented so that its area receives the maximum magnetic flux. A switch is opened in the solenoid circuit and its current drops to 0 in 15.0 ms. (a)What is the initial magnetic flux through the inner coil? (b) Determine the average induced EMF in the small coil during the 15.0 ms. (c) If you look along the long axis of the solenoid so that the official 10.0 A current is clockwise, determine the direction of the induced current in the small inner coil during the time that the current drops to zero. (d) What is the magnitude of the average induced current in the coil?


    2. Relevant equations
    I don't know which equation I need!



    3. The attempt at a solution
    I have solved everything up until part d. I don't know which equation I need to use to find the average induced current in the inner coil.
    This is what I have done for parts a through c:
    a) B=μnI
    B= 4∏x10^-7(5000/.200)10.0= 0.31416 F
    [itex]\Phi[/itex]=BAcosθ
    0.31416(∏0.003^2)cos(0)= 8.88x10^-6 Wb
    b) [ε]=-N(Δ[itex]\Phi[/itex]/Δt)
    -100(8.88x10^-6/0.015)= 0.059 V
    c) CCW

    Thanks so much for your help! And if you wouldn't mind checking the parts I completed I would be so grateful!
     
  2. jcsd
  3. Jul 13, 2012 #2

    TSny

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    Homework Helper
    Gold Member

    For (d) use your result from (b) and the given resistance of the coil. Think Ohm's law.

    You might want to reconsider your answer to (c). Note, in this problem the flux through the coil decreases when the switch is opened.
     
  4. Jul 13, 2012 #3
    Haha of course! I feel silly for not thinking of that. Thanks so much TSny!
     
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