Formula for gravitational energy

[wolram]

i have looked on the net for a formula that would give me an idea
of how much gravitational energy verses other energies is given
of when a massive body is destroyed, is there such a formula?
or is it just that the mass of the body is converted into energy by
E=M^2 and the gravitational energy that, that the origonal body
exhibited?

 

[HallsofIvy]

I have no idea at all what this question means!

What do you mean by "gravitational energy"? Is there any reason to think that the energy contained in a body can be allocated to "gravity", "electricity", etc?

"or is it just that the mass of the body is converted into energy by
E=M^2" Typo here: E= M c^2.

Yes, there is not differentiation into "types" of energy.

 

[wolram]

not very well posed and typos also, maybe if i ask,
if two bodies collied and are totaly destroyed, gravitational
radiation is given out, "hopefully", how would the total amount of this radiation
be measured? i hope this makes more sence.

 

[NateTG]

Originally posted by wolram
not very well posed and typos also, maybe if i ask,
if two bodies collied and are totaly destroyed, gravitational
radiation is given out, "hopefully", how would the total amount of this radiation
be measured? i hope this makes more sence.

Huh? If two collide, they are not totally destroyed. If you look at collisions, matter is rearranged, not destroyed.

If you're referring to a matter/antimatter reaction, you should still get gravitation from the cosmic rays that are formed from the colision.

 

[wolram]

significant or not the LIGO project is attempting to detect GRAVITATIONAL
RADIATION, so how are the parameters set, i would WAG that less
than the origonal bodies "potential gravitational energy"
is converted into gravitational radiation, maybe 10% or less,
so has anyone who can understand my ramblings any idea of how
many "ERGs or what ever" of gravitational energy is release
when a mass is converted to energy?