Formula for gravity/circular motion in terms of V? (i think )

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Discussion Overview

The discussion revolves around the relationship between gravitational force and circular motion, specifically how to express gravitational force in terms of velocity (V) for an object in orbit. Participants explore the equations governing these forces and the implications of mass cancellation in the equations.

Discussion Character

  • Technical explanation
  • Mathematical reasoning

Main Points Raised

  • One participant presents the equations for gravitational force (Fg) and centripetal force (Fc), leading to the equation mv²/r = Gm(1)m(2)/r².
  • There is a question regarding which mass should be canceled out in the equation, prompting a discussion about the roles of the masses involved.
  • Another participant suggests that the mass of the Earth is the one that remains after cancellation, as it is the mass exerting the gravitational force on the orbiting object.
  • A later reply confirms the approach of applying Newton's second law to the orbiting object, leading to the equation V²/R = GM_{earth}/R².
  • Participants discuss the cancellation of the mass of the object in revolution, indicating it is the mass acted upon by the centripetal force.

Areas of Agreement / Disagreement

Participants generally agree on the approach to the problem and the mass that should remain after cancellation, but there is some initial uncertainty regarding which mass to cancel.

Contextual Notes

The discussion does not resolve the broader implications of the equations or any potential assumptions regarding the conditions of the orbit.

Who May Find This Useful

This discussion may be useful for students studying gravitational forces and circular motion, particularly those looking to understand the mathematical relationships between these concepts.

tman12345
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If F=mg, and Fc=Fg, Fc=mv2/r (thats v squared; my apologies, i have no idea how to use the superscript button), and Fg=Gm(1)m(2)/r2 (squared), where m(2) is the mass of, say, the earth, and m(1) is the mass of the object orbiting the earth. By substituting these equations together, we get

mv2/r=Gm(1)m(2)/r2,

and we can cancel out the r on the left, and the m (which is mass). but I have a problem; which mass is canceled out on the right side? is it the mass of the object or mass of the earth?


thanks
 
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Which do you think? Which mass is executing circular motion as it orbits the other? Which mass are you finding the centripetal force on?
 
I think i am supposed to be finding it with respect to the earth, so I believe then the mass of the Earth is what is left
 
tman12345 said:
I think i am supposed to be finding it with respect to the earth, so I believe then the mass of the Earth is what is left
Right.

Force on orbiting object due to gravity: [tex]F = GM_{earth}M_{object}/R^2[/tex]

Applying Newton's 2nd law to orbiting object: [tex]F = M_{object}V_{object}^2/R[/tex]

Combined:

[tex]M_{object}V_{object}^2/R = GM_{earth}M_{object}/R^2[/tex]

[tex]V_{object}^2/R = GM_{earth}/R^2[/tex]
 
Cancel out mass of object in revolution,thats the mass acted upon by the centripetal force.
 
thanks a lot! that really helped.
next time ill try to not leave my physics book at school over the weekend
 

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