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Formula relation to charge and time?

  1. May 14, 2007 #1
    My circuit analysis professor put the following formula on the blackboard today:

    [tex]Q(t_1) = \int_{t_0}^{t_1} idt +q(t_0)[/tex]

    What does this mean in relation to charge and time? He said that [tex]q(t_0)[/tex] is the initial charge.
     
    Last edited: May 14, 2007
  2. jcsd
  3. May 15, 2007 #2

    Pyrrhus

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    Homework Helper

    Look it this way:

    [tex] \frac{dQ}{dt} = i [/tex]

    [tex] \int_{t_{0}}^{t_{1}} dQ = \int_{t_{0}}^{t_{1}} idt [/tex]

    Then what follows is what your teacher wrote. Look at the first equation with the concept of derivative in mind...
     
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