1. The problem statement, all variables and given/known data Four very long, current-carrying wires in the same plane intersect to form a square with side lengths of 31.0 cm, as shown in the figure (Figure 1) . The currents running through the wires are 8.0 A, 20.0 A, 10.0 A, and I. Find the magnitude of the current that will make the magnetic field at the center of the square equal to zero. Picture here: http://session.masteringphysics.com/problemAsset/1003626/14/yf_Figure_28_35.jpg 2. Relevant equations B = μ0I/2πr 3. The attempt at a solution I know the steps and solution, but what I'm not clear about is how the right hand rule is used to determine the direction of the magnetic field. Where exactly do you position your hand? On top of the wire? To the left of it? To the right of it? How much do you curl? All the way around? Here is the solution: μ0I/2πr where r = distance of B from the wire. r = .5 ( 31cm) = .155m μ0=4π*10^-7 ƩB = 0 = μ0/2πr * (I - 10 - 8 + 20) 0 = I - 10 - 8 + 20 = I + 2 I = -2A Magnitude of I = abs(I) = 2A So using the right hand rule, why is 20 positive whereas 10 and 8 are negative? Assuming that into the page/monitor is negative, shouldn't the B on the 20A also go into the page/monitor via RHR?