Four very long, current carrying wires in the same plane

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Homework Help Overview

The problem involves four long, current-carrying wires arranged in a square formation, with the objective of determining the current that results in a zero magnetic field at the center of the square. The currents are specified as 8.0 A, 20.0 A, 10.0 A, and an unknown current I.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the right hand rule to determine the direction of the magnetic field generated by each wire. There is uncertainty about how to correctly position the hand and interpret the signs associated with the currents.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the right hand rule and its implications for the magnetic field directions. Some guidance has been provided, but there remains a lack of consensus on the interpretation of the signs for the magnetic fields produced by the currents.

Contextual Notes

There is mention of the original poster's understanding of the steps involved in the solution, but confusion persists regarding the application of the right hand rule and the resulting magnetic field directions. The thread also indicates that it has been active for a considerable duration, suggesting a potential need for revisiting foundational concepts.

penguinnnnnx5
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Homework Statement


Four very long, current-carrying wires in the same plane intersect to form a square with side lengths of 31.0 cm, as shown in the figure (Figure 1) . The currents running through the wires are 8.0 A, 20.0 A, 10.0 A, and I.

Find the magnitude of the current that will make the magnetic field at the center of the square equal to zero.

Picture here:
http://session.masteringphysics.com/problemAsset/1003626/14/yf_Figure_28_35.jpg

Homework Equations



B = μ0I/2πr

The Attempt at a Solution



I know the steps and solution, but what I'm not clear about is how the right hand rule is used to determine the direction of the magnetic field.

Where exactly do you position your hand? On top of the wire? To the left of it? To the right of it? How much do you curl? All the way around?

Here is the solution:

μ0I/2πr where r = distance of B from the wire.

r = .5 ( 31cm) = .155m
μ0=4π*10^-7

ƩB = 0 = μ0/2πr * (I - 10 - 8 + 20)
0 = I - 10 - 8 + 20 = I + 2
I = -2A

Magnitude of I = abs(I) = 2A

So using the right hand rule, why is 20 positive whereas 10 and 8 are negative? Assuming that into the page/monitor is negative, shouldn't the B on the 20A also go into the page/monitor via RHR?
 
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hi penguinnnnnx5! :smile:
penguinnnnnx5 said:
… what I'm not clear about is how the right hand rule is used to determine the direction of the magnetic field.

your thumb points along the current

your fingers curl round the wire in the same direction that the circular magnetic field lines curl round the wire :wink:
So using the right hand rule, why is 20 positive whereas 10 and 8 are negative?

the point is to the left of the 20 but to the right of the 10 and 8

so your fingers are coming out of the page through that point for the 20, but going into the page for the 10 and 8 :smile:
 
tiny-tim said:
hi penguinnnnnx5! :smile:your thumb points along the current

your fingers curl round the wire in the same direction that the circular magnetic field lines curl round the wire :wink:the point is to the left of the 20 but to the right of the 10 and 8

so your fingers are coming out of the page through that point for the 20, but going into the page for the 10 and 8 :smile:

buddy u didnt answer dang
 
freeform2745 said:
buddy u didnt answer dang

This thread is almost 10 years old.

It was the responsibility of the original poster to ask further questions if tiny-tim's answer was not sufficiently clear to the poster. I can assure you that tiny-tim would have artfully guided the poster to a complete understanding of the solution. tiny-tim was one of the best homework helpers that Physics Forums has ever had.
 
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