Fourier Series for a Square-wave Function

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SUMMARY

The discussion focuses on determining the Fourier series expansion for a square wave function defined by y(t) = h when 0 ≤ (t + nT) ≤ 1 and y(t) = 0 elsewhere, with a period T = 2. The Fourier analysis coefficients were simplified to A_n = h/πn sin(πn). It was noted that since sin(πn) equals zero for integer values of n, the coefficients A_n vanish for all integer n. The discussion also highlighted that defining x(t) = y(t) - h/2 results in an odd function, which simplifies the Fourier series analysis.

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Homework Statement



Consider the square wave function defined by y(t) = h (constant) when 0 ≤ (t + nT) ≤1,
y(t) = 0 elsewhere, where T = 2 is the period of the function. Determine the Fourier series
expansion for y(t).

Homework Equations



Fourier Analysis Coefficients

The Attempt at a Solution



Please look at the attachment, I am not convinced I have done it right so far... please help.
 

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Your answer for ##A_n## can be simplified. Since ##T=2##, it becomes
$$A_n = \frac{h}{\pi n} \sin(\pi n)$$
Now what is ##\sin(\pi n)##?
 
By the way, you can save yourself some work as follows. Note that if we define ##x(t) = y(t) - h/2##, then ##x## is an odd function. What can you say about the Fourier series of an odd function? And how does the Fourier series of ##x## relate to the Fourier series of ##y##?
 

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