Fourier Series for Periodic Functions - Self Study Problem

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SUMMARY

The discussion focuses on the Fourier Series for periodic functions, specifically analyzing the coefficients A0, An, and Bn for a function f(x) with a periodicity of 2π. The equations provided include A0 = (2/L)∫Xo}^{Xo+L}f(x)dx, An = (2/L)∫Xo}^{Xo+L}f(x)cos(2πrx/L)dx, and Bn = (2/L)∫Xo}^{Xo+L}f(x)sin(2πrx/L)dx. The attempt at a solution indicates A0 = C, An = 0, and Bn = (-C/πr)cos(πr). Additionally, there is a critique regarding the clarity of the image provided and the correctness of the Bn formula, particularly for even indices.

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  • Understanding of Fourier Series and periodic functions
  • Familiarity with integral calculus
  • Knowledge of trigonometric functions and their properties
  • Ability to interpret mathematical notation and equations
NEXT STEPS
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  • Learn about the convergence of Fourier Series
  • Explore the implications of even and odd functions in Fourier analysis
  • Investigate applications of Fourier Series in signal processing
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Students and educators in mathematics, particularly those studying calculus and Fourier analysis, as well as professionals in engineering and physics who apply Fourier Series in practical scenarios.

Gopal Mailpalli
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Self Study
1. Homework Statement

Consider a periodic function f (x), with periodicity 2π,
h3YE5bX.jpg

Homework Equations


##A_{0} = \frac{2}{L}\int_{X_{o}}^{X_{o}+L}f(x)dx##
##A_{n} = \frac{2}{L}\int_{X_{o}}^{X_{o}+L}f(x)cos\frac{2\pi rx}{L}dx##
##B_{n} = \frac{2}{L}\int_{X_{o}}^{X_{o}+L}f(x)sin\frac{2\pi rx}{L}dx##

The Attempt at a Solution


##A_{0} = C##
##A_{n} = 0##
##B_{n} = \frac{-C}{\pi r}cos\pi r##
http://imgur.com/a/4Q2oL
 
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Gopal Mailpalli said:
Self Study
1. Homework Statement

Consider a periodic function f (x), with periodicity 2π,
h3YE5bX.jpg

Homework Equations


##A_{0} = \frac{2}{L}\int_{X_{o}}^{X_{o}+L}f(x)dx##
##A_{n} = \frac{2}{L}\int_{X_{o}}^{X_{o}+L}f(x)cos\frac{2\pi rx}{L}dx##
##B_{n} = \frac{2}{L}\int_{X_{o}}^{X_{o}+L}f(x)sin\frac{2\pi rx}{L}dx##

The Attempt at a Solution


##A_{0} = C##
##A_{n} = 0##
##B_{n} = \frac{-C}{\pi r}cos\pi r##
http://imgur.com/a/4Q2oL
This post should have been sent to Calculus and Beyond Forum.

Your picture is hardly readable. Better to type the text in, or write it clearly and make a better picture.
The formula for the b coefficients is not correct. What happens in case of even index? What is b2, for example?
 

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