The problem is finding the fourier series of f(t) = e^(-t) from [0,2] where T=2 and without using complex solution.
f(t) = a0/2 + ∑ (anCos(nωt) +bnsin(nωt)
NOT using f(t) = ∑dne^(inωt)
The Attempt at a Solution
I tried once but got completly wrong answer.
it was ∑(4*(-1)n+1*e-2+n2π2*e-2*(-1)n+1+4+n2π2) / n2π2
When I graphed this up in my texas it showed like a barcode which is definetly wrong.
When I got this solution what I did was extending the function f(t) to be even from [-2,2] and T=4 and went from there so all the bn would be equal to zero but that was as far as I got. What am I doing wrong here?
Thank you :)