Fourier Transform of a function squared.

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SUMMARY

The discussion centers on the Fourier Transform of a function squared, specifically analyzing the equation \(u_t = -u_{nxxx} - 3(u^2)_{nx}\). The participants confirm that the reduction of the Fourier Transform is correct, leading to the expression \(-\mathcal{F}^{-1}\left[\mathcal{F}\left[u_{nxxx} - 3(u^2)_{nx}\right]\right] = ik^3\mathcal{F}^{-1}\left[\mathcal{F}(u)\right] - ik\mathcal{F}^{-1}\left[\mathcal{F}(u^2)\right]\). Furthermore, it is established that \(\mathcal{F}(u^2) = \mathcal{F}(u\cdot u)\) cannot be further reduced.

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Consider \(u_t = -u_{nxxx} - 3(u^2)_{nx}\).

The Fourier Transform is linear so taking the Inverse Fourier transform of the Fourier Transform on the RHS we have
\begin{align}
-\mathcal{F}^{-1}\left[\mathcal{F}\left[u_{nxxx} - 3(u^2)_{nx}\right]\right] &= -\mathcal{F}^{-1} \left[\mathcal{F}\left[(ik)^3u\right]\right] - 3\mathcal{F}^{-1}\left[\mathcal{F} \left[(ik)u^2\right]\right]\\
&= ik^3\mathcal{F}^{-1}\left[\mathcal{F}(u)\right] - ik\mathcal{F}^{-1}\left[\mathcal{F}(u^2)\right]
\end{align}
  1. Is the above reduction correct?
  2. Can \(\mathcal{F}(u^2) = \mathcal{F}(u\cdot u)\) be further reduced?
 
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Yes, the reduction is correct. You cannot further reduce \(\mathcal{F}(u^2) = \mathcal{F}(u\cdot u)\).
 

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