MHB Fourier Transform of a function squared.

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The discussion focuses on the Fourier Transform of a function squared, specifically analyzing the equation \(u_t = -u_{nxxx} - 3(u^2)_{nx}\). It confirms that the reduction using the Inverse Fourier Transform is correct, leading to the expression involving \(ik^3\mathcal{F}^{-1}[\mathcal{F}(u)]\) and \(-ik\mathcal{F}^{-1}[\mathcal{F}(u^2)]\). Additionally, it asserts that \(\mathcal{F}(u^2) = \mathcal{F}(u\cdot u)\) cannot be simplified further. The key takeaway is the validation of the Fourier Transform operations and their implications on the function squared. Understanding these transformations is crucial for analyzing differential equations in mathematical physics.
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Consider \(u_t = -u_{nxxx} - 3(u^2)_{nx}\).

The Fourier Transform is linear so taking the Inverse Fourier transform of the Fourier Transform on the RHS we have
\begin{align}
-\mathcal{F}^{-1}\left[\mathcal{F}\left[u_{nxxx} - 3(u^2)_{nx}\right]\right] &= -\mathcal{F}^{-1} \left[\mathcal{F}\left[(ik)^3u\right]\right] - 3\mathcal{F}^{-1}\left[\mathcal{F} \left[(ik)u^2\right]\right]\\
&= ik^3\mathcal{F}^{-1}\left[\mathcal{F}(u)\right] - ik\mathcal{F}^{-1}\left[\mathcal{F}(u^2)\right]
\end{align}
  1. Is the above reduction correct?
  2. Can \(\mathcal{F}(u^2) = \mathcal{F}(u\cdot u)\) be further reduced?
 
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Yes, the reduction is correct. You cannot further reduce \(\mathcal{F}(u^2) = \mathcal{F}(u\cdot u)\).
 

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