Fourier transform of Bessel function

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The discussion centers on finding the Fourier transform of the Bessel function J_0(x) using the result from a previous part of the homework. The Fourier transform of f(x) = 1/√(1-x²) is established as √(π/2)J_0(-k). Participants suggest leveraging the even nature of J_0(k) and the Fourier inversion theorem to aid in the solution. There is a focus on understanding the application of derivative rules in Fourier transforms to derive the necessary results. The conversation emphasizes the importance of connecting previous findings to solve the current problem effectively.
bobred
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Homework Statement


Noting that J_0(k) is an even function of k, use the result of part (a) to
obtain the Fourier transform of the Bessel function J_0(x).

Homework Equations


In (a) I am asked to show that the Fourier transform of
f(x)=\dfrac{1}{\sqrt{1-x^{2}}}
is
\tilde{f}(k)=\sqrt{\pi/2}J_0(-k)
where
J_0(x)=\frac{1}{\pi}\int_{0}^{\pi} e^{i x \cos \theta}d \theta

The Attempt at a Solution


I have found the Fourier transform of f(x) using trig substitution I just can't see how to get the FT of J_0(x).
Any hints as to where I should begin?
 
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Have you heard of the Fourier inversion theorem?
Make use of that, and the hint that question provided about the even nature of the Bessel function.
 
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Likes bobred
Hi
I went over my notes a few times and got it.
Thanks
 
Considering the second derivative of
png.latex?J_0%28x%29.png
show the Fourier transform of
png.latex?J_2%28x%29.png
is

D_2%28x%29=%5Csqrt%7B%5Cfrac%7B2%7D%7B%5Cpi%7D%7D%5Cfrac%7B1-2k%5E2%7D%7B%5Csqrt%7B1-k%5E2%7D%7D.png


I have done similar for
png.latex?J_1%28x%29.png
using rules for derivatives of Fourier transforms but can't see where to start, where the numerator
png.latex?1-2k%5E2.png
comes from.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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