Fourier Transform of exponential and heaviside function

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The discussion focuses on computing the Fourier transform of the function φ(t) = e^(-at)H(t), where H(t) is the Heaviside step function. Participants express confusion about the role of the Heaviside function, particularly in determining the limits of integration. It is suggested to split the integral into two parts: one from -∞ to 0 and the other from 0 to ∞, leveraging the properties of H(t). By substituting f(t) into the Fourier transform definition, the integration simplifies due to H(t) being zero for negative t. This approach clarifies how to effectively set up and solve the problem.
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Homework Statement


Compute the Fourier transform of

\phi(t)=(e^(-at))H(t)

where H(t) is the Heaviside step function


Homework Equations





The Attempt at a Solution


I am stuck in an attempt at the solution, I am confused at how the heaviside step function factors in and think that it may just affect the upper and lower limits of the integral, but am not sure. I am looking for direction on how to approach the problem or at least set it up.
 
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The Fourier Transform is defined on a function f(t) as:

\int_{-\infty}^\infty f(t) e^{2 \pi i t \omega} dt

Now, try plugging in f(t)=e^(-at)H(t) into this definition. Remember that H(t) is defined to be 0 for all negative t and 1 for all positive t, so try splitting the integral into two integrals: one with lower bound -infinity and upper bound 0, and the other with lower bound 0 and the upper bound infinity. Then apply the definition of H(t) and it should become easy.
 
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