Solving Fraction Function Homework: (x+1)/(x+6) >or= 0

  • Thread starter Thread starter shoook
  • Start date Start date
  • Tags Tags
    Fraction Function
AI Thread Summary
To solve the inequality (x+1)/(x+6) ≥ 0, identify critical points where the numerator and denominator change signs, specifically at x = -1 and x = -6. Analyze the sign of the expression in three intervals: x < -6, -6 < x < -1, and x > -1. In the interval x < -6, the expression is positive; between -6 and -1, it is negative; and for x > -1, it is positive again. Include the endpoints x = -1 and x = -6 since the inequality is non-strict. The solution set is x ≤ -6 or x ≥ -1.
shoook
Messages
23
Reaction score
0

Homework Statement



Solve: (x+1)/(x+6) >or= 0



Homework Equations





The Attempt at a Solution



Don't know where to even start.
 
Physics news on Phys.org
List all of the x values where the numerator and denominator of the left hand side can change signs. Quick!
 
x=-1 x=-6 ?
 
Great! So if x<-6 what's the sign? If -6<x<-1, what's the sign? If x>-1, what's the sign? You only have three cases. Since it's >or=, you should think about x=-1 and -6 as well.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
Back
Top