How Do You Draw a Free Body Diagram for a Box and Truck in Motion?

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The discussion focuses on drawing free-body diagrams for a box and a truck in motion. For the box, key forces include its weight downward, a normal force upward, and a friction force acting to the right, with an unlabelled vector possibly representing acceleration to the left. For the truck, the forces include a reaction force from the tires pushing backward, a normal force from the ground, the truck's weight downward, and a friction force from the box acting to the left, along with an unlabelled vector to the right. Participants express uncertainty about the direction and role of the unlabelled vectors and the interactions between the box and the truck. Understanding these forces is essential for accurately depicting the motion dynamics in the diagrams.
plshelpme
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Homework Statement

A large box containing your new computer sits on the bed of your pickup truck. You are stopped at a red light. The light turns green and you stomp on the gas and the truck accelerates. To your horror, the box starts to slide toward the back of the truck. (Assume that the truck is accelerating to the right.)

part 1)
Draw clearly labeled free-body diagram for the box
given the following vectors:
1] weight of box
2] normal force
3] box's friction force on the truck
4] unlabelled vector

part2)
Draw clearly labeled free-body diagram for the truck.
(The bed of the truck is not frictionless.)
given the following vectors:
1] reaction force to tires' backward push
2] normal force from ground
3] weight of truck
4] reaction to the normal force on the box from the truck
5] the box's friction force on the truck
6] unlabelled vector

Homework Equations





The Attempt at a Solution



part a attempt is

weight downwards
normal force upwards
box's friction force on the truck to the right
unlabelled vector (not sure it used as a accelerating vector of the box) to the left

part b attempt is

1] reaction force to tires' backward push - to the right
2] normal force from ground - upwards
3] weight of truck - downwards
4] reaction to the normal force on the box from the truck - upwards
5] the box's friction force on the truck - to the left
6] unlabelled vector - to the right

i am not sure of the answers...
 
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plshelpme said:
part a attempt is

weight downwards
normal force upwards
box's friction force on the truck to the right
unlabelled vector (not sure it used as a accelerating vector of the box) to the left

part b attempt is

1] reaction force to tires' backward push - to the right
2] normal force from ground - upwards
3] weight of truck - downwards
4] reaction to the normal force on the box from the truck - upwards
5] the box's friction force on the truck - to the left
6] unlabelled vector - to the right

i am not sure of the answers...

In Part a, your Force vector on the box = m*a the acceleration in the frame of reference of the truck bed I think.

In b) I would make the normal force = truck + box
And what is the unlabeled vector to the right? Isn't that the reaction force on the ground already? The tires are pushing a force to the left aren't they if the truck is moving right?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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