Free Fall and gravitational field strength

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SUMMARY

Free fall occurs when an object's acceleration matches the gravitational field strength at that location, which on Earth is approximately 9.8 m/s². In scenarios such as an airplane accelerating downwards at this rate, individuals experience weightlessness due to the absence of normal force. Regarding black holes, their gravitational field strength is not infinite at all distances; it resembles that of a normal star until reaching the singularity, where gravitational forces become extreme.

PREREQUISITES
  • Understanding of gravitational field strength
  • Basic knowledge of free fall physics
  • Familiarity with concepts of acceleration
  • Introduction to black hole physics
NEXT STEPS
  • Research the principles of gravitational acceleration
  • Study the effects of free fall in varying gravitational fields
  • Explore the physics of black holes and singularities
  • Learn about the concept of weightlessness in different contexts
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Students of physics, aerospace engineers, and anyone interested in gravitational phenomena and the behavior of objects in free fall.

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Hello.

For free fall to occur, does the rate at which you fall have to equal the gravitational field strength at that point above the surface?

If I'm in an airplane and accelerate towards the ground at an acceleration of 9.8ms^-2 equal to that of the Earth's gravitational field, then I experience zero g and therefore, weightlessness.

Is that right?

Also, if this is correct, and hypothetically I travel towards a black hole whose gravitational field strength is infinite, how would this work?

Help please!
 
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That is the condition for free fall.

A black hole's gravitational field strength is not infinite everywhere; from a distance, it has more or less the same gravitational field as any normal star of the same mass. It would only be (supposedly) infinite at the singularity.
 

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