Free Fall Equations on hot air balloon

AI Thread Summary
A hot-air balloon descends at 2.0 m/s when a passenger drops a camera from 45m above the ground. To find the time it takes for the camera to reach the ground and its velocity just before landing, the appropriate equations of motion must be applied. The discussion emphasizes the need to rearrange the equations to isolate time and correctly account for the direction of motion. The quadratic formula is suggested as a method to solve for time after substituting the known values into the equations. Understanding these concepts is crucial for solving similar physics problems.
matace50
Messages
3
Reaction score
0

Homework Statement



A hot-air balloon is descending at a rate of 2.0 m/s when a passenger drops a camera. If a camera is 45m above the ground when it is dropped, (a) how long does it take for the camera to reach the ground(b) what is the velocity just before it lands? Let upward be the positive direction for this problem.


Homework Equations


I have to use either 2a x change in displacement= final velocity^2 - initial velocity^2 or
change in displacement= 1/2a x t^2 + initial velocity x change in time

a = acceleration t= time ^2= squared x= multiply

The Attempt at a Solution



I think i somehow have to rearrange the equation to isolate t but i have no idea how. Can anyone help
 
Physics news on Phys.org
For the first part, use the equation:

d = v1*t + (1/2)at^2

careful about signs... decide first if you want upward to be positive, or downward to be positive...
 
I see, but the problem doesn't give me time. I plugged everything in, but i still can't seem to get time.

(just started physics 2 weeks ago so I am kind of confused)
 
matace50 said:
I see, but the problem doesn't give me time. I plugged everything in, but i still can't seem to get time.

(just started physics 2 weeks ago so I am kind of confused)

You have to use the quadratic formula to solve for time.
 
Ok now i understand. Thanks
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top