- #1
a18c18
- 21
- 0
Homework Statement
A stone is thrown upward at an angle of 51° above the horizontal. Its maximum height during the trajectory is 26 m. What was the stone's initial speed?
m/s
Homework Equations
a=v2/r
v2=vo2+2ax
C=2[tex]\pi[/tex]r
The Attempt at a Solution
I figured the acceleration is 9.81*sin51 since it just gravity when thrown upward so now I have to account for gravity.
so a=7.62
I plugged this into a=v2/r in order to find velocity:
7.62=v2/26
so v=14.079
The distance I got by using the equation C=2[tex]\pi[/tex]r
I got that C=163.36 and the distance is 1/4th of the circumference since the ground and highest point are perpendicular. I got 40.84 for the distance
I then plugged my answers for a, v and distance into v2=vo2+2ax to find initial velocity
I got that v=20.596 but this was incorrect. Does anyone know what I did wrong?
Thank you!