1. The problem statement, all variables and given/known data A small piece of Styrofoam packing material is dropped from a height of 2.00 m above the ground. Until it reaches terminal speed, the magnitude of its acceleration is given by a = -g + bv. After falling 0.500 m, the Styrofoam effectively reaches terminal speed, and then takes 5.00 s more to reach the ground. (a) What is the value of the constant b? (b) What is the acceleration at t = 0? (c) What is the accleration when the speed is 0.150 m/s? 2. Relevant equations ƩF=ma W = weight FD = resistant force 3. The attempt at a solution I drew a free body diagram with the resistance force pointing up and the weight pointing down, where up is positive. ƩF=W-FD=ma -mg + bv = ma -(1)g + bv = (1)a -g + bv = a bv-g = 0 b = g/v I am stuck here because I am not sure how to find the terminal velocity. Do I do v=x/t=0.05/0.150=10/3≈3.33 m/s??? That would make b = 9.8/(10/3)=2.94Kg/s, which seems too high...Can anyone help? Thanks.