Frequency changes in respect to moving sources and observers

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SUMMARY

The discussion centers on the Doppler effect as it relates to a moving train emitting sound. When the train approaches a station, the frequency heard by observers at the station is calculated using the formula f1 = f/(1 - (Vs/Vsound)). Conversely, when the train recedes, the formula changes to f1 = f/(1 + (Vs/Vsound)). Passengers on the train perceive the emitted frequency directly, as they are moving with the source of the sound, confirming that they hear the original frequency without alteration.

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Aphrael
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I am a little confused about the change in frequencies. I am working on a problem involving a train. The train is moving at a constant velocity and blows its horn at a certain frequency.

I know that the frequency heard by those on the train station will be f1= f/(1-(Vs/Vsound)) when the train is approaching the station where Vs is the constant spead of the train and Vsound is the speed of sound.

I also know that the frequency heard by those on the train station will be f1= f/(1+(Vs/Vsound)) when the train is receding from the station.

However, what is the sound heard by the people on the train. I thinking that as the passengers are moving at the same velocity as the train they would therefore hear the frequency the train was emitting. Is this correct and if not where am I going wrong in my thinking?
 
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This is indeed correct.

--------
Assaf
http://www.physicallyincorrect.com/"
 
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