Frequency Response Function - Random Vibration

Click For Summary
The discussion focuses on analyzing the frequency response function of an elevated water tank subjected to earthquake-induced ground acceleration. The tank's parameters include a mass of 2x10^6 kg, a natural frequency of 10.6 rad/s, and a critical damping coefficient of 12%. The user seeks to derive the frequency response function for the tank's displacement relative to the ground, as well as the mean square and standard deviation of that displacement. They have made progress by formulating the equations of motion and substituting input displacement to find the response, and they are looking for confirmation on their approach. The conversation highlights the complexities of dynamic response analysis in engineering applications.
Dunc26
Messages
1
Reaction score
0
Hi looking for some help on the below I'm a little bit stuck.

The effect of an earthquake on an elevated water tank is to be investigated. The water tank has mass m=2x10^6 kg and natural frequency wn=10.6 rad/s and a damping coefficient of 12% critical damping.
Ground acceleration can be approximated by constant spectrum So=0.0075m2/s3
Obtain:
i) The frequency response function for the displacement of tank mass relative to the ground
ii) Mean square response of displacement
iii) Standard deviation of displacement

Frequency Response = Output / Input

mz"+cz'+kz=-my" .......Eq 1

Where z is the relative displacement
and y is input

I've done some work on something similar in the past where I have used the Force input to the system to get the frequency response function and obtain the equation:

H(w) = 1 / (k-(mw^2)+icw

This gives the frequency response function of the elevated mass displacement relative to the input force?

Using the equation: mz"+cz'+kz=-my"

If I take the input displacement
y = Ae^iwt (where A is a constant then)
y' = iwtAe^iwt
y"= -w^2.Ae^iwt

The output would then be
z = Be^iwt
z' = iwtBe^iwt
z" = -w^2.Be^iwt

subtituting into Eq 1

(k+iwc-mw^2)B.e^iwt = (mw^2)A.e^iwt

Therefore response is equal to B/A
= (mw^2) / (k+iwc-mw^2)

Is this along the correct lines??
 
Last edited:
Physics news on Phys.org
could anyone shed some light on this question? i have the same problem (saves me writing a new thread etc.)
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 11 ·
Replies
11
Views
5K
Replies
12
Views
6K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
4K
Replies
2
Views
3K