Friction of rubber box on concrete floor

Click For Summary
SUMMARY

The discussion centers on calculating the friction force acting on a 10 kg rubber box resting on a concrete floor when a horizontal force of 200 N is applied. The maximum static friction force is determined using the equation Fsmax = μs η, where the coefficient of friction (μs) between rubber and concrete is established as 1.00. The net force must be zero for the box to remain at rest, indicating that the friction force equals the applied force until it exceeds the maximum static friction threshold. Therefore, the friction force is 200 N until the box begins to slide.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of static and kinetic friction concepts
  • Familiarity with calculating weight using η = mg
  • Ability to apply the equation Fsmax = μs η
NEXT STEPS
  • Research the implications of static vs. kinetic friction in real-world applications
  • Learn about different coefficients of friction for various material pairs
  • Explore advanced topics in dynamics, such as friction in motion analysis
  • Investigate the effects of surface texture on friction coefficients
USEFUL FOR

Physics students, educators, and engineers interested in mechanics, particularly those focusing on frictional forces and their applications in real-world scenarios.

anon3005
Messages
1
Reaction score
0

Homework Statement


A 10 kg rubber box is resting on a concrete floor. A force of 200 N is then applied to this box in a horizontal direction. What is the magnitude of the friction force on the box?

Homework Equations


This is a question about applying Newton's laws so Fsmax = μs η and η = mg.

The Attempt at a Solution


I have had answers -200 N, 98.1N, and 200N in which they are all incorrect. I have an idea it could be 0 N since the net force would have to be 0 since it is at rest and there is a static friction present but I am not sure.
 
Physics news on Phys.org
anon3005 said:

Homework Statement


A 10 kg rubber box is resting on a concrete floor. A force of 200 N is then applied to this box in a horizontal direction. What is the magnitude of the friction force on the box?

Homework Equations


This is a question about applying Newton's laws so Fsmax = μs η and η = mg.

The Attempt at a Solution


I have had answers -200 N, 98.1N, and 200N in which they are all incorrect. I have an idea it could be 0 N since the net force would have to be 0 since it is at rest and there is a static friction present but I am not sure.
What is the co-efficient of friction between rubber and concrete? Is that given? If not, I think you should look it up.
 
cnh1995 said:
What is the co-efficient of friction between rubber and concrete? Is that given? If not, I think you should look it up.

It's 1.00
 
anon3005 said:
It's 1.00
So what's the equation?
 
Is the question asking about the friction force before it starts sliding, or after (assuming it slides)?
 
James R said:
Is the question asking about the friction force before it starts sliding, or after (assuming it slides)?
Given the coefficient of friction, it is safe to assume it slides.
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
2
Views
3K