Friction problem of a block sandwiched between 2 surfaces

Click For Summary

Homework Help Overview

The discussion revolves around a friction problem involving a block sandwiched between two fixed surfaces, with a focus on the forces acting on the block when a horizontal force is applied. The participants explore the conditions under which the block begins to move and the relationship between the static friction forces from the two surfaces.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants question the ratio of static friction forces (F1 and F2) acting on the block and whether they reach their thresholds simultaneously or in a specific ratio based on the coefficients of friction. There is also discussion about the conditions under which the block will start to move and the implications of static indeterminacy.

Discussion Status

Some participants have provided insights into the behavior of the friction forces and the conditions for movement, suggesting that one surface will slip first while the other will engage immediately. There is ongoing exploration of the implications of different coefficients of friction and the need for moment equilibrium.

Contextual Notes

The problem is noted to be statically indeterminate, and there are references to the need for satisfying moment equilibrium, which may complicate the assumptions about friction coefficients.

vcl0124
Messages
8
Reaction score
0
Thread moved from the technical forums to the schoolwork forums
I don't know how to post a picture so I tried my best to describe my question in words.

X is horizontal, Y is vertical and there is no gravity effect.

There is a block is sandwiched by 2 surfaces (top surface and bottom surface). Both surfaces are fixed in X direction and the bottom surface is also fixed in Y direction. There is a downward force N pushing the top surface. The static friction coefficient between block and 2 surfaces are different (let's say u1, u2 and u1<u2). If I pull the block with a X direction force F. My understanding is I need F>N(u1+u2) to make the block start moving. For F<N(u1+u2), there will be static friction (F1 and F2) to cancel F and keep the block static. So my question is F1 and F2 will be in 1:1 ratio (F1 reach the static friction threshold first) or they will be in u1:u2 ratio (F1 and F2 reached the static friction threshold together)?

Looking forward to an answer. Thanks a lot!
 
Physics news on Phys.org
Welcome to PF.

We are looking forward to an annotated diagram.
There is an "attach files" button below the edit area, that will load a .jpg file.
 
Untitled.png


Does this help?
 
vcl0124 said:
So my question is F1 and F2 will be in 1:1 ratio (F1 reach the static friction threshold first) or they will be in u1:u2 ratio (F1 and F2 reached the static friction threshold together)?
One surface will slip first, but the other will immediately come into play, so it will appear to be coincident.
The friction force, needed to move the block, will be; F = N * ( u1 + u2 ) .
 
Baluncore said:
One surface will slip first, but the other will immediately come into play, so it will appear to be coincident.
The friction force, needed to move the block, will be; F = N * ( u1 + u2 ) .
Thanks a lot! Let me assume some numbers to verify whether I understand you answer correctly. Assume N=1, u1=0.3 and u2=0.5. So the F1 and F2 vs F will be like A plot not B plot. Is it what you mean?
Untitled.png
 
The CoF is not relevant, until something slips.
The block will settle, clamped symmetrically between the two surfaces, presumably with the same force from each surface.
Diagram A is more realistic.
 
vcl0124 said:
Thanks a lot! Let me assume some numbers to verify whether I understand you answer correctly. Assume N=1, u1=0.3 and u2=0.5. So the F1 and F2 vs F will be like A plot not B plot. Is it what you mean?View attachment 348569
The problem is statically indeterminate:
https://en.wikipedia.org/wiki/Statically_indeterminate

Note that you also need to satisfy moment equilibrium. So if the static friction forces were different, the normal forces on the block would have to redistribute to counter that. This could lead to edge loading, and the assumptions about the friction coefficient might not be valid anymore.
 
Last edited:

Similar threads

  • · Replies 15 ·
Replies
15
Views
1K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
Replies
13
Views
3K
Replies
61
Views
3K
Replies
15
Views
3K
Replies
16
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K