Friction problem of playground slide

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A child accelerates down a playground slide at 1.40 m/s² on a 29.0-degree incline, prompting a discussion on finding the coefficient of kinetic friction without knowing the child's mass. Participants emphasize that the mass is irrelevant, as it will cancel out in calculations. A free body diagram is recommended to visualize the forces acting on the child. By assigning an arbitrary mass, the problem can be simplified, demonstrating that the solution is independent of mass. Ultimately, the coefficient of friction can be determined without needing the child's weight.
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Homework Statement



A child goes down a playground slide with an acceleration of 1.40 m/s2. Find the coefficient of kinetic friction between the child and the slide if the slide is inclined at an angle of 29.0 degrees below the horizontal.

Homework Equations


Normal force = force of gravity (f_g) cos theta
F_f kinetic = mu_k . normal force



The Attempt at a Solution


here weight of the child is not given. so could someone help me how to approach such problem?

Thanks in advance
 
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The mass is irrelevant.

\vec F=m\vec a
 
I am still confused how to approach the problem without knowing the mass?
could anybody explain little more?

Thanks in advance
 
pttest said:
I am still confused how to approach the problem without knowing the mass?
could anybody explain little more?

Thanks in advance


Forget about the mass for the time being, start by drawing a free body diagram with all the forces acting.
 
pttest said:
I am still confused how to approach the problem without knowing the mass?
could anybody explain little more?

Thanks in advance

Yeah, do what rock.freak suggested. Just assign the mass of the child an arbitrary value, m, and see where that gets you. You'll see soon enough what we meant by 'irrelevant.' It'll cancel out.

Remember, the coefficient of friction is a pure number. Unless you've got more than one mass that you can add up and divide one by another, it is dimensionally impossible to incorporate the mass of the child into your solution, and as such, the problem boils down to one of two cases. Either its unsolvable (It isn't) or the solution is independent of the mass.

Solving the problem will prove that the latter is correct.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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