Frictional Forces and Stopping Distance in Physics

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SUMMARY

The discussion focuses on calculating the stopping distance of a car traveling at 49.0 mi/h under different conditions of friction. When the coefficient of static friction (µs) is 0.099, the minimum stopping distance is determined using the formula derived from Newton's laws and the work-energy principle. Conversely, with a dry surface where µs is 0.596, the stopping distance significantly decreases. Additionally, the kinetic energy (KE) per kilogram of the car is calculated to understand the impact of speed on stopping distance.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of the work-energy principle
  • Familiarity with the concept of friction and coefficients of friction
  • Basic algebra for solving equations
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  • Calculate stopping distances using different coefficients of friction
  • Explore the relationship between kinetic energy and stopping distance
  • Learn about the effects of weather conditions on road friction
  • Investigate advanced physics concepts related to motion and forces
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Physics students, automotive engineers, and anyone interested in understanding the dynamics of vehicle stopping distances under varying conditions of friction.

Susie babe
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A car is traveling at 49.0 mi/h on a horizontal highway.

(a) If the coefficient of static friction between road and tires on a rainy day is 0.099, what is the minimum distance in which the car will stop?

(b) What is the stopping distance when the surface is dry and µs = 0.596?Thank you, oh and please don't give me only the answer, the full solution would be very much helpful.
 
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How would you find the frictional force exerted on the car?

If the car is traveling at 49.0 miles per hour, how much KE per kg will the car have? i.e. KE/mass ?

Final Hint: what is the work done by the frictional force (think of the definition of work done by a force)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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