1. The problem statement, all variables and given/known data A 0.5 kg wooden block is placed on top of a 1.0kg block. The coefficient of static friction between the two blocks is 0.35. The coefficient of kinetic friction between the lower block and the level table is 0.2. What is the maximum horizontal force that can be applied to the lower block without the upper block slipping? The correct answer on the sheet is 8.1N 2. Relevant equations aΔt=v2-v1 d= 1/2(v1 + v2)∆t d=v1Δt + 1/2aΔt^2 v2^2=v1^1 + 2ad F=ma μ=Ff/Fn 3. The attempt at a solution (9.8)(0.2)=Ff of bottom 1kg box 1.96N=Ff (0.5)(0.35)=Ff for top 0.5 kg box 0.175N=Ff Unsure of the next step. I assumed the force would be equal to the frictional force of the bottom box but it is not.