im struggling abit with this question. i have a formula but it doesnt really go with my question(adsbygoogle = window.adsbygoogle || []).push({});

a brake disc has the following specification

mean radius 0.16m

force applied to each pad 5045N

U = 0.35

brake disc rotational speed is 550rev/min

work out its frictional torque

work done a min by this torque

heat energy generated pers second

i science for motor vehicle engineers by peter twigg and the book has a very similar example. but it has a brake cycliner in the equation which i dne have and hydraulic oil pressure.

i have the formula total braking force per disc = n x U x P x A (n)

in my case i take that to be 550 x 0.35 x 5.045Kn x 0.16

this gives me 155N of frictional torque per disc.

am i going along the right sort of lines or am i using the completely wrong forumla?

looking around alot fo other examples have time bt as i dnt have this im abit lost.

any help would be very much appriated :)

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# Frictional toruq of a brake disc

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