From where the E inside the battery comes from?

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    Battery
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Discussion Overview

The discussion revolves around the origin of the electric field inside a battery and the processes that lead to the establishment of potential difference when a circuit is connected. It touches on concepts related to electric fields, potential difference, and the role of chemical reactions within the battery.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • One participant questions the source of the electric field inside the battery, noting that work is required to move positive charges against the electric field to establish a potential difference.
  • Another participant states that the electromotive force (EMF) exists within the battery even before any external circuit is connected, suggesting that this is a fundamental property of batteries.
  • A third participant explains that the redox chemical reactions within the battery create ions that move to their respective terminals, generating an electric field and potential difference as charges accumulate.

Areas of Agreement / Disagreement

Participants express different perspectives on the mechanisms behind the electric field and potential difference in batteries, indicating that multiple competing views remain without a consensus on the exact source of the electric field.

Contextual Notes

Some statements rely on assumptions about the behavior of electric fields and the nature of chemical reactions in batteries, which may not be fully explored in the discussion.

kashan123999
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So as I am junior high school student just learned that when the terminals of wire are connected to a battery,an E (electric field) is established inside the battery from positive to negative end/terminal (How did I assumed one as positive and one as negative? COnvention regarding electric fields,am i right?),Work is required to push say,positive charges from negative terminal to positive terminal i.e against the electric field (WHY? obviously to build potential/potential difference b/w both ends) so the work is done by the energy provided by the battery,When positive end would be have charges and negative end do not have them...obviously the current would start to flow from positive to negative terminal...all of this is actually conventional current..

My question is,from where the Electric field inside the battery comes from?
 
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kashan123999 said:
So as I am junior high school student just learned that when the terminals of wire are connected to a battery,an E (electric field) is established inside the battery from positive to negative end/terminal (How did I assumed one as positive and one as negative? COnvention regarding electric fields,am i right?),Work is required to push say,positive charges from negative terminal to positive terminal i.e against the electric field (WHY? obviously to build potential/potential difference b/w both ends) so the work is done by the energy provided by the battery,When positive end would be have charges and negative end do not have them...obviously the current would start to flow from positive to negative terminal...all of this is actually conventional current..

My question is,from where the Electric field inside the battery comes from?

The EMF is present inside the battery before any external circuit is connected. Have a read through this introductory article at wikipedia:

http://en.wikipedia.org/wiki/Battery_(electricity )

:smile:
 
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berkeman said:
The EMF is present inside the battery before any external circuit is connected. Have a read through this introductory article at wikipedia:

http://en.wikipedia.org/wiki/Battery_(electricity )

:smile:

thank you i would surely read it as well :)
 
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The redox chemical reaction moves the ions to their respective terminals creating an electric field and potential difference. Once charges accumulate at the terminals, the redox process is propelling ions to move against the electric field. This increases the voltage at the terminals (potential difference) as well as increase the E field energy. Did I help?

Claude
 

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