I was reading a link i found here on physicsforums called "The relativistic rocket".(adsbygoogle = window.adsbygoogle || []).push({});

There was lots of calculations of the required fuel for certain distances and such.

However, I understand that time→0 when our velocity v→c.

And that will mean we travel a larger distance for a shorter amount of time in our (he/she who travels) frame of reference, right?

During that time though, we are using fuel, so my question is, or maybe I should call this a statement, however. Doesn't this mean that the fuel required to travela distance dalsogoes to zero?.

Fuel required→0 when v→c because t→0

I mean, the engine "stops" in it's frame of reference (as time is felt for the engine) when v is c, right? Let's now say it's possible to reach the velocity c.

Let's sayvis now(9999999999999/10000000000000)*c. If statement above is true, this velocity will give a very large distance traveled for a minimal used up fuel.

Or is all this nonsense?

Very thanks in advance.

/Robin Andersson

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# Fuel per unit distance decreasing?

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