starkind said:
Hmmm.
Consider two otherwise equivalent cars at full stop. One starts out and accelerates slowly until it reaches highway speed one minute later. The other floors the pedal and (no skid marks) reaches highway speed in ten seconds. They both drive to the end of a sufficiently long course, and then stop. Do they both use the same amount of gas?
Moving the same mass the same distance means the same amount of work?
Then the best move would be to accelerate to speed in as short a time as possible, keeping in mind safety.
This is actually a very interesting question. The answer is of course quite complex and might have several answers.
Given that the kinetic energy of an object is equal to 1/2mv^2, one might assume that the petrol energy required to accelerate a vehicle to speed would be the same for all cases.
I'll simplify the problem by having two vehicles reach their destination at the point the slower accelerating car reaches the target speed of say, 50 mph.
Fast car accelerates at 50mph/60 seconds.
Slow car accelerates at 50mph/60 minutes.
So the slow car travels 25 miles getting to it's target speed and takes an hour to get there.
The fast car takes about 30 minutes to arrive.
In this example, the slow car would have to get twice the fuel mileage than that of the faster car in order to win the mpg race.
Now this is just my opinion, but I think the fast car would win the mpg contest.
The other extreme of course, is the quarter mile dragster, which interestingly, gets about 1/4 mile per gallon. Pitted against the slow car above, it would probably lose the mpg contest.
These are extreme cases, but I think it points out that there may be an optimal acceleration for every vehicle, when considering fuel economy.