Function for y(x,t) wave some questions

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Homework Help Overview

The problem involves determining the function y(x, t) for a wave traveling along a string, given specific parameters such as wave speed, frequency, and initial conditions for displacement and velocity.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the wave function using the cosine form and is uncertain about the amplitude and phase constant. Some participants confirm the vertical displacement at the origin and suggest it corresponds to the amplitude. Others raise questions about how to derive the amplitude and phase constant from the given conditions.

Discussion Status

Participants are actively discussing the derivation of the wave function and exploring the relationships between the parameters. Some guidance has been provided regarding the displacement at the origin, but there is still uncertainty about determining the amplitude and phase constant.

Contextual Notes

There are references to similar problems and the need to derive parameters from initial conditions, indicating a potential lack of clarity in the original problem setup.

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Homework Statement


A wave travels along a string in the positive x-direction at 33 m/s. The frequency of the wave is 48 Hz. At x = 0 and t = 0, the wave velocity is 2.8 m/s and the vertical displacement is y = 3 mm. Write the function y(x, t) for the wave. (Use the following as necessary: x and t. Assume x and y are in m, and that t is in s.)


The Attempt at a Solution



y(x,t) = Acos(kx - wt)
should be the formula

i'm assuming A = 0.003m but it is not so i don't know

w = 2 * pi * f (frequency)
= 2 * pi * 48Hz
= 301.59

k = w / v
= 301.59 / 33(m/s)
= 9.139

so what i have now is y(x,t) = Acos(9.139x - 301.59t + something)

how do i find the amplitude and the missing something if there is one?

thank you
 
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your vertical displacement y(x,t) would be 3mm since at t=0 and x=0 , y=3mm

y(x,t) = Acos( k(0) - w(0)) = A(1) = 3mm = 0.003m

what you have looks right to me. Sorry if its not to clear, it's been a long summer
 
Liquidxlax said:
your vertical displacement y(x,t) would be 3mm since at t=0 and x=0 , y=3mm

y(x,t) = Acos( k(0) - w(0)) = A(1) = 3mm = 0.003m

what you have looks right to me. Sorry if its not to clear, it's been a long summer



one example was this question

A wave travels along a string in the positive x-direction at 31 m/s. The frequency of the wave is 47 Hz. At x = 0 and t = 0, the wave velocity is 2.8 m/s and the vertical displacement is y = 3 mm. Write the function y(x, t) for the wave. (Use the following as necessary: x and t. Assume x and y are in m, and that t is in s.)

the answer was 0.0099 * sin(9.53*x - 295.31*t + 2.84)

i know how to get the k and w which was 9.53 and 295.31
but i don't know how to get 0.0099 and 295.31 are
thank you

i know how to get the k and w which are 9.
 
Find the velocity of the piece of string at x=0, t=0, by taking the time derivative of your function. Then there two equations for the unknown amplitude A and phase constant (something:smile:)

ehild
 

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