Function Waves Graph Homework: Find λ for tp=3.5s and xp=3.7m

Click For Summary
SUMMARY

The discussion focuses on solving a physics homework problem involving the function y(x, t) = Asin(kx−ωt+ϕ) to find the wavelength (λ) given specific time (tp = 3.5 s) and position (xp = 3.7 m) values. The correct wavelength is determined to be 7 meters based on the first graph, which spans from x = 0 to x = 7. The equation λ = 2π/k is highlighted as essential for calculating the wavelength, with k being derived from the graph's characteristics.

PREREQUISITES
  • Understanding of wave functions, specifically sinusoidal functions.
  • Familiarity with the relationship between wavelength (λ), wave number (k), and angular frequency (ω).
  • Basic knowledge of graph interpretation in the context of physics.
  • Ability to manipulate and solve equations involving trigonometric functions.
NEXT STEPS
  • Study the derivation and application of the wave equation y(x, t) = Asin(kx−ωt+ϕ).
  • Learn how to calculate wave number (k) from graphical data.
  • Explore the relationship between wavelength (λ) and frequency (f) in wave mechanics.
  • Investigate the implications of fixed time and variable position in wave graphs.
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics, as well as educators looking for examples of wave function applications in homework scenarios.

negation
Messages
817
Reaction score
0

Homework Statement



The function y(x, t) = Asin(kx−ωt+ϕ) where x is in metres and t in seconds for
(a) tp = 3.5 s and (b) xp = 3.7m

The Attempt at a Solution



I don't even know where to begin.

I know λ = 2pi/k

this is really disorienting. In the first graph, I'm given t = 3.5.
A = 3
y(x,t) = 3sin(kx-3.5ω)

In the second graph, y(x,t) = 3sin(3.7k - ωt)

Really, I don't know how should I get started and I'm really frustrated.

I'm asked to find the wavelength. Is it 7m based off the first graph or do I have to utilize t = 3.5 and x=3.7?
 

Attachments

  • Capture.PNG
    Capture.PNG
    14.5 KB · Views: 481
Last edited:
Physics news on Phys.org
Hello again,

Let's try to get you unfrustrated. The problem statement apparently includes a question like: what is the wavelength ? (because you mention it under 3). And it has something to do with k (because you include it under 3 -- but λ = 2pi/k looks more like a relevant equation to me than an attempt at solution -- Please make it easier for yourself and be a bit more complete under 1) and 2) ).

1.) I see an A = 3 falling out of the air. Where does it come from ?

2.) If the first plot is for a fixed t, the only thing that varies is x and you have a plot of A sin(kx + something). How would you find k and, thereby λ (according to relevant equation 1) ? Is this part of a longer exercise, or is the second plot there just to confuse you ?
 
BvU said:
Hello again,

Let's try to get you unfrustrated. The problem statement apparently includes a question like: what is the wavelength ? (because you mention it under 3). And it has something to do with k (because you include it under 3 -- but λ = 2pi/k looks more like a relevant equation to me than an attempt at solution -- Please make it easier for yourself and be a bit more complete under 1) and 2) ).

1.) I see an A = 3 falling out of the air. Where does it come from ?

2.) If the first plot is for a fixed t, the only thing that varies is x and you have a plot of A sin(kx + something). How would you find k and, thereby λ (according to relevant equation 1) ?


Is this part of a longer exercise, or is the second plot there just to confuse you ?

Hi BVU,

I'm overlooking certain aspects in this question.

It's part of a longer question but I had it solved.

I am asked to find the wavelength given the 2 graph. The wavelength of a wave is simply taken to be the length of a wave per cycle.
In the first graph, the wavelength is 7m. This turns out to be correct. It starts at x =0 and ends at x=7.
What had me confused was the given tp and xp.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
5
Views
3K
  • · Replies 9 ·
Replies
9
Views
5K
Replies
2
Views
2K
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
16K
  • · Replies 13 ·
Replies
13
Views
2K