birulami
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From http://www.us.oup.com/us/catalog/general/subject/Physics/Relativity/?view=usa&ci=9780198567325" I learn that the fundamental identity
c^2\text{d}{t'}^2 -\text{d}{x'}^2 -\text{d}{y'}^2 -\text{d}{z'}^2<br /> =<br /> c^2\text{d}{t}^2 -\text{d}{x}^2 -\text{d}{y}^2 -\text{d}{z}^2
relates co-ordinates of one inertial frame S' to another one called S. By putting the point in the origin of S' and re-arranging we get
c^2(\frac{\text{d}{t'}}{\text{d}{t}})^2<br /> +(\frac{\text{d}{x}}{\text{d}{t}})^2 <br /> +(\frac{\text{d}{y}}{\text{d}{t}})^2 <br /> +(\frac{\text{d}{z}}{\text{d}{t}})^2<br /> = c^2
or, in short, |v|=c.
This nicely shows time dilation, since the term \text{d}t'/\text{d}t represents the speed of clocks in S', and \text{d}t' is called, I think, proper time of S'. We see how \text{d}t'/\text{d}t goes to zero, i.e. time stops, as spatial velocity approaches c. On the other extreme, if spatial velocity goes to zero, the term goes to 1, i.e. \text{d}t'=\text{d}t showing that time in S' now develops as fast as time in S.
In the latter situation, i.e. relative spatial velocity zero, put S and S' into an area with gravity such that S' suffers stronger gravity. Then afaik time runs slower in S', but this would mean that |v|=c does not hold anymore. Consequently (?) the fundamental identity does not hold anymore. Not a surprise since the fundamental identity stems from SRT which does not take gravity into account.
The question is: Is there a similarly easy to understand fundamental identity in GR and how does it look like?
Thanks,
Harald.
c^2\text{d}{t'}^2 -\text{d}{x'}^2 -\text{d}{y'}^2 -\text{d}{z'}^2<br /> =<br /> c^2\text{d}{t}^2 -\text{d}{x}^2 -\text{d}{y}^2 -\text{d}{z}^2
relates co-ordinates of one inertial frame S' to another one called S. By putting the point in the origin of S' and re-arranging we get
c^2(\frac{\text{d}{t'}}{\text{d}{t}})^2<br /> +(\frac{\text{d}{x}}{\text{d}{t}})^2 <br /> +(\frac{\text{d}{y}}{\text{d}{t}})^2 <br /> +(\frac{\text{d}{z}}{\text{d}{t}})^2<br /> = c^2
or, in short, |v|=c.
This nicely shows time dilation, since the term \text{d}t'/\text{d}t represents the speed of clocks in S', and \text{d}t' is called, I think, proper time of S'. We see how \text{d}t'/\text{d}t goes to zero, i.e. time stops, as spatial velocity approaches c. On the other extreme, if spatial velocity goes to zero, the term goes to 1, i.e. \text{d}t'=\text{d}t showing that time in S' now develops as fast as time in S.
In the latter situation, i.e. relative spatial velocity zero, put S and S' into an area with gravity such that S' suffers stronger gravity. Then afaik time runs slower in S', but this would mean that |v|=c does not hold anymore. Consequently (?) the fundamental identity does not hold anymore. Not a surprise since the fundamental identity stems from SRT which does not take gravity into account.
The question is: Is there a similarly easy to understand fundamental identity in GR and how does it look like?
Thanks,
Harald.
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