Fundamental Resonant Frequency of a Waveguide

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SUMMARY

The fundamental resonant frequency of a rectangular waveguide with a cutoff frequency of 6.5 GHz and a length of 30 mm can be determined using the dispersion relation formula. For a closed cavity, the fundamental mode is identified as the 001 mode, and the resonant frequency is calculated using the equation f = c * (q / (2L))², where L is the cavity length and q is the mode number. The discussion clarifies that the length of the cavity influences the resonant frequency, and the fundamental mode remains consistent regardless of the cavity's length, provided the dimensions of the waveguide remain unchanged.

PREREQUISITES
  • Understanding of waveguide theory and modes
  • Familiarity with the dispersion relation for waveguides
  • Knowledge of electromagnetic wave propagation
  • Basic mathematics involving frequency calculations
NEXT STEPS
  • Study the dispersion relation for rectangular waveguides
  • Learn about the different modes of rectangular waveguides and cavities
  • Explore the impact of cavity length on resonant frequencies
  • Investigate the effects of open vs. closed ends on waveguide modes
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Electrical engineers, physicists, and students studying waveguide theory and resonant frequency calculations will benefit from this discussion.

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Homework Statement



For a given rectangular waveguide the cut off frequency of the fundamental mode is 6.5GHz. What is the fundamental resonant frequency of a 30mm long cavity made from the same waveguide?


Homework Equations



Unsure


The Attempt at a Solution



I would have thought that if the rectangular waveguide dimensions didn't change then the fundamental mode would still be 6.5GHz.

I am unsure of how the length contributes to the resonant frequency...

Any help would be great.
 
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What are the modes of a rectangular waveguide (open on both ends w, with width a and height b)? Which one is the fundamental mode?

What are the modes of a rectangular cavity (closed on both ends, w/ length l=30\text{mm}, same width and height as the previous one)? Which one is the fundamental mode?
 
I'm assuming the cavity is closed at both ends as such the fundamental mode would be along the length (i.e. the 001 mode). As such using the equation derived from the dispersion relation

f=c((\frac{q}{2L})2)1/2

would give the fundamental frequency. With L= 30mm, q = Mode Number (1), c=Speed of Light

I think that this would be correct for a closed cavity, but is it possible of the long end is open?
 

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