F(x) = ∫ cos (1+t^2)^-1) from 0 to 2x - x^2
Determine whether F has maximum or minimum value
The Attempt at a Solution
I tried finding
F'(x) = Dx (∫ cos (1+t^2)^-1) from 0 to 2x - x^2)
What do I do next? equate F'(x) = 0 and find F''(x) ?
Please help. Thank you.