Fundamental Theorem of Calculus

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SUMMARY

The discussion focuses on determining the maximum or minimum values of the function F(x) defined as F(x) = ∫ cos((1+t^2)^-1) dt from 0 to 2x - x^2. The first derivative, F'(x), is calculated as F'(x) = (2-2x)cos[(1+(2x-x^2))^-1]. To find critical points, participants emphasize the necessity of setting F'(x) = 0 and analyzing the second derivative, F''(x), to ascertain the nature of these critical points.

PREREQUISITES
  • Understanding of integral calculus, specifically the Fundamental Theorem of Calculus
  • Knowledge of differentiation techniques, including the product and chain rules
  • Familiarity with the concepts of maxima and minima in calculus
  • Ability to compute and interpret first and second derivatives
NEXT STEPS
  • Practice solving integrals involving trigonometric functions and their inverses
  • Learn how to apply the second derivative test for identifying maxima and minima
  • Explore the implications of critical points in the context of real-world applications
  • Study the behavior of functions defined by definite integrals and their derivatives
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Students studying calculus, educators teaching integral and differential calculus, and anyone interested in optimizing functions using calculus principles.

inter060708
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Homework Statement



F(x) = ∫ cos (1+t^2)^-1) from 0 to 2x - x^2

Determine whether F has maximum or minimum value

Homework Equations





The Attempt at a Solution


I tried finding
F'(x) = Dx (∫ cos (1+t^2)^-1) from 0 to 2x - x^2)
= (2-2x)cos[(1+(2x-x^2))^-1]

What do I do next? equate F'(x) = 0 and find F''(x) ?

Please help. Thank you.
 
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Hey inter060708 and welcome to the forums.

Turning points happen when the derivative is zero, and the second-derivative (unless it's an inflexion point) will determine whether something is a minimum of maximum based on the sign.

Remember that the second derivative says how fast the derivative is changing, so if it is negative then it means you have a maximum and if it's positive it means a minimum since the derivative (which is the rate of change) will be either 'going negative' or 'going positive'.

So the first thing you need to do is find F'(x) = 0 and take it from there.
 

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