How to Calculate Heat Transfer Rate Through a Furnace Wall?

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Homework Help Overview

The discussion revolves around calculating the heat transfer rate through a furnace wall, characterized by its area, thickness, thermal conductivity, and a specified temperature. Participants are examining the implications of the given temperature value in the context of typical furnace operations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are questioning whether the given temperature of 40K represents a temperature difference rather than an absolute temperature, considering the context of furnace operations. There is discussion about the typical temperature ranges expected in such scenarios and the implications of the provided data on the calculation.

Discussion Status

Some participants have offered insights regarding the interpretation of the temperature value, suggesting it may be a delta T. Others have expressed uncertainty about the adequacy of the information provided to proceed with the calculations, indicating a lack of consensus on the interpretation of the problem.

Contextual Notes

There is a noted concern about the potential for a typo in the temperature value, as typical furnace temperatures are expected to be significantly higher than the given 40K. This raises questions about the assumptions being made in the absence of additional information.

ash-kennard
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Homework Statement



a furnace wall has an area of 3m^2. a thickness of 250mm and a thermal conductivity of 1.5 W m^-1 K^-1. calculate the rate of heat transfer through it when the temperature is 40K

Homework Equations



Q/t=KxAx(T2-T1)/L

The Attempt at a Solution



This isn't homework as such, it was given in a list of questions aimed at helping with revision for my module exam. I've done the other 11 questions but this one is doing my head in. the furthest I've gotten to is (Q/18t)-40=T2 but without knowing T2 or the transfer rate is it impossible to progress to an answer?

please help. don't want to be revising something incorrectly for the exam
 
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40K must be the temperature difference (delta T) it surely isn't -233 C for a furnace.
 
i was talking to my dad about it earlier today too. but that's the exact question, haven't re worded it at all. a furnace implies very hot temperatures, and the 40k must have to be a difference. but i wanted to see if i was overlooking something so posted on here.

is there anyway to get any further on this question with the lack of information?
 
I don't see any other way to solve this problem rather than to assume a delta T of 40 K. But actually that value seems to low. Furnace temperatures get very high, I would have expected a delta T of about 350 K assuming an exterior surface temperature of about 40 C (100 F) and an inside wall temperature of 380 C (800 F). Might be a typo.
 
right cheers for that then. i know how to do it providing that is is delta 40, i also know how to do it given 2 temperatures so cheers for the help. was annoying me greatly

much appreciated, ash
 

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