Galilean principle of relativity

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SUMMARY

The Galilean principle of relativity asserts that physical laws maintain the same form across different inertial frames related by Galilean transformations. This includes transformations involving rotation, boost, and translation in space and time, represented mathematically in homogeneous coordinates. Newton's second law, expressed as F=m·a, remains invariant under these transformations, confirming that forces and accelerations transform consistently. Understanding Galilean spacetime is crucial for grasping these principles, particularly in the context of world lines and force fields.

PREREQUISITES
  • Galilean transformations in physics
  • Newton's laws of motion
  • Homogeneous coordinates in mathematics
  • Concept of inertial frames of reference
NEXT STEPS
  • Study the mathematical representation of Galilean transformations
  • Explore the implications of Newton's second law in different frames
  • Investigate the concept of world lines in spacetime
  • Learn about the differences between Galilean and Lorentz transformations
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Students of physics, particularly those focusing on classical mechanics, as well as educators and researchers interested in the foundational principles of relativity and motion.

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A Galilean transformation consists of a rotation (in space), a boost (in space) and a translation (in space and time). This can be represented for homogeneous coordinates as

<br /> \left[\begin{matrix}t&#039;\\x&#039;\\y&#039;\\z&#039;\\1\end{matrix}\right]=<br /> <br /> \left[\begin{matrix}<br /> 1&amp;0&amp;0&amp;0&amp;t_{t}\\<br /> u_{x}&amp;R_{11}&amp;R_{12}&amp;R_{13}&amp;t_{x}\\<br /> u_{y}&amp;R_{21}&amp;R_{22}&amp;R_{23}&amp;t_{y}\\<br /> u_{z}&amp;R_{31}&amp;R_{32}&amp;R_{33}&amp;t_{z}\\<br /> 0&amp;0&amp;0&amp;0&amp;1<br /> \end{matrix}\right]<br /> <br /> \cdot\left[\begin{matrix}t\\x\\y\\z\\1\end{matrix}\right]<br />

To me there seem to be two principles of relativity in frames that are related by a Galilean transformation. The first says that all physical laws described in Galilean space-time have the same form in frames related by a Galilean transformation. Newton's second law of motion for example given by F=m.a in one frame becomes F&#039;=m.a&#039; in the second frame, while F and F&#039; transform under a Galilean transformation.

The second says that all physical laws are the same in frames that are related by a Galilean transformation with R=id (i.e. inertial frames of reference). Again Newton's second law of motion: F=F&#039; and a=a&#039;.

Is this a correct understanding of Galilean relativity?
 
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Actually I'm really having problems with the concept of Galilean relativity and I think it is because I don't understand Galilean spacetime properly. Consider a world line and its underlying spatial trajectory
<br /> \bar{w}\colon \mathbb{R}\to \mathbb{R}^{4}\colon t \mapsto (t,\bar{x}(t))<br />
<br /> \bar{x}\colon \mathbb{R}\to \mathbb{R}^{3}\colon t \mapsto (x,y,z)<br />
where \mathbb{R}^{3} with the Euclidean structure and \mathbb{R}^{4} with the Galilean structure. The acceleration of the world line is given by
<br /> \bar{a}\colon \mathbb{R}\to \mathbb{R}^{4}\colon t\mapsto \frac{d^{2}\bar{w}}{dt^{2}}=(0,\frac{d^{2}\bar{x}}{dt^{2}})\equiv(0,\tilde{a}(t))<br />
A force field is given by \bar{F}\colon \mathbb{R}^{4}\to \mathbb{R}^{3} and it can be evaluated along a world line by using \bar{F}(\bar{w}(t))=m \tilde{a}(t) When change frame using a Galilean transformation
<br /> t=t&#039;+t_{t}\quad\quad \bar{x}=t&#039;\bar{u}+R\cdot\bar{x}&#039;+\bar{t}_{\bar{x}}<br />
we find that
<br /> \tilde{a}(t)=R\cdot \tilde{a}&#039;(t&#039;)\Leftrightarrow \bar{F}(\bar{w}(t))=m\tilde{a}(t)=m R\cdot \tilde{a}&#039;(t&#039;)=R\cdot \bar{F}(\bar{w}&#039;(t&#039;))<br />

So for inertial frames (R=id) we find that \bar{F}(\bar{w}(t))=\bar{F}(\bar{w}&#039;(t&#039;)). Is this then the second aspect of Galilean relativity? And what about the other aspect that states that laws have the same form after a Galilean transformation?

Both aspects of invariance are for example discussed here.
 
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