Gamma as a Jacobian of Lorentz transformations

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The Jacobian of a Lorentz transformation is equal to 1, indicating that the measure remains invariant in special relativistic field theories. Consequently, the action can be defined without considering scalar density subtleties. In contrast, for general coordinate transformations, the measure is not invariant, leading to a different form of the action that includes a square root of the determinant of the metric. The gamma factor is integral to the Lorentz transformation but does not influence the Jacobian. Thus, gamma's role is distinct from that of the Jacobian in these transformations.
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Hello. When one is converting between coordinate systems, the Jacobian arises as a necessary consequence of the conversion. Does this occur with transformations between relativistic systems, and, if so, is this manifested through the prevalence of gamma in the transforms?

Any guidance would be appreciated. Thanks!
 
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No. The Jacobian of a Lorentz transformation is 1. That's why in special relativistic field theories you don't need to consider the subtlety that the measure is actually a scalar density., and you can define

<br /> S[\phi] = \int d^4 x L<br />

For general coordinate transformations the measure is NOT invariant, and you would obtain the action

<br /> S[\phi] = \int \sqrt{|g|}d^4 x L<br />

The squareroot becomes 1 for the Minkowski metric.

The gamma is part of the Lorentz transformation itself, NOT of the corresponding Jacobian.
 
For a relatively lowbrow discussion, see p. 629 of this book: http://www.lightandmatter.com/lm.pdf
 
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