Gauss' Law for a Nonuniform Field

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SUMMARY

The discussion centers on Gauss' Law applied to a nonuniform electric field defined by E = 3*x xhat N/C. The closed rectangular surface has dimensions a = b and c, with the left edge at x = a. Participants concluded that despite the absence of enclosed charge, the flux through the surface can be nonzero due to the varying electric field, indicating that charge must exist within the box to account for the observed net flux.

PREREQUISITES
  • Understanding of Gauss' Law
  • Familiarity with electric fields and flux concepts
  • Knowledge of vector calculus
  • Experience with integral calculus for evaluating surface integrals
NEXT STEPS
  • Study the implications of nonuniform electric fields on Gauss' Law
  • Learn how to calculate electric flux through various surfaces
  • Explore the relationship between enclosed charge and electric field strength
  • Investigate the applications of Gauss' Law in different geometrical configurations
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Physics students, educators, and anyone studying electromagnetism, particularly those focusing on electric fields and their applications in real-world scenarios.

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Homework Statement


A closed rectangular surface with dimensions a = b and c where the faces perpendicular to the field are a*b. The left edge of the closed surface is located at position x = a, for c > a.The electric field throughout the region is nonuniform and given by E = 3*x xhat N/C,

Homework Equations


Flux = Integral of E(dot)dA = qenclosed/Epsilon0

The Attempt at a Solution


I'm just wondering about how this works, if there is no enclosed charge, then there shouldn't be a net flux.

I'm pretty sure the flux at one end is greater as it reaches the x = c face than at x = a, is it possible to have a nonzero net flux?
 
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Conclusion: there is charge in the box.
 
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