Gauss' Law for Infinite Sheets of Charge

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The discussion revolves around calculating the electric field at two points, A and B, due to three parallel infinite sheets of charge with varying charge densities. It is noted that the electric field from an infinite sheet of charge is constant and does not depend on distance. The total electric field at point A is derived from the sum of the fields produced by all three sheets, while some participants suggest that the fields at points A and B should be equal. Clarification is provided that the sheets do not block each other's fields, which is crucial for understanding the superposition principle. The use of Gauss' Law is also mentioned as a valid approach to solve the problem.
kazukamikaze
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Homework Statement


Three parallel, infinite, insulating planes (sheets) of charge are arranged as shown (see attached image). Note carefully the charge desnitties and distances given. From left to right the charge densities are -3σ, +σ, +σ. How does the magnitude of the electric field at point a compare to the magnitude of the field at point b?

Homework Equations


E = σ/2ε0

The Attempt at a Solution


From what I recall from my lecture, the E field of an infinite sheet of charge does not depend on distance. Second, I believe that the field lines look something like what I've drawn in the second attached image. For that reason, I argued the magnitude of A was larger than B as the charge density of the sheet is larger.
 

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kazukamikaze said:

Homework Statement


Three parallel, infinite, insulating planes (sheets) of charge are arranged as shown (see attached image). Note carefully the charge desnitties and distances given. From left to right the charge densities are -3σ, +σ, +σ. How does the magnitude of the electric field at point a compare to the magnitude of the field at point b?

Homework Equations


E = σ/2ε0

The Attempt at a Solution


From what I recall from my lecture, the E field of an infinite sheet of charge does not depend on distance. Second, I believe that the field lines look something like what I've drawn in the second attached image. For that reason, I argued the magnitude of A was larger than B as the charge density of the sheet is larger.

Homework Statement


Homework Equations


The Attempt at a Solution


The field at A is going to be the sum of the fields from all three plates, isn't it?
 
Dick said:
The field at A is going to be the sum of the fields from all three plates, isn't it?

Based off what one of my classmates told me, the field at the two points should be equal.

The only way I can rationalize these answer is by taking the sum of the three plates. I'm just confused as to why this is done.
 
kazukamikaze said:
Based off what one of my classmates told me, the field at the two points should be equal.

The only way I can rationalize these answer is by taking the sum of the three plates. I'm just confused as to why this is done.

Because the plates don't block the fields coming from the other plates, if that's what the confusion is. You could also directly use Gauss' theorem.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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