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Gauss' Law: Infinite plane with charge

  1. Oct 21, 2015 #1
    1. The problem statement, all variables and given/known data
    An infinite plane of charge has surface charge density 6.8 µC/m2. How far apart are the equipotential surfaces whose potentials differ by 100 V? In mm

    2. Relevant equations
    E=σ/(2ε0)

    3. The attempt at a solution
    So first I solved for E= 6.8e-6/(2*8.85e-12) = 384170.791

    then because ΔV= E *ΔX
    so
    ΔX=ΔV/E

    so then I substituted
    ΔX = 100/ 384170.791
    ΔX = .0002603

    The site says that I've made a power of ten error the answer must be in mm but I'm not sure what Im doing wrong
     
  2. jcsd
  3. Oct 21, 2015 #2

    gneill

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    Staff: Mentor

    So far you've expressed your ΔX in meters. What value did you enter for your answer in mm? How many significant figures did you provide?
     
  4. Oct 21, 2015 #3
    I entered 2.603 mm
     
  5. Oct 21, 2015 #4

    gneill

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    Staff: Mentor

    Numerically the result looks to be good. How many significant figures do the given data support?
     
  6. Oct 21, 2015 #5
    I realized my mistake its supposed to be .2603mm I converted from Meters to millimeters improperly. Thank you.
     
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