Gauss Law Problem With A Spherical Conductive Shell

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SUMMARY

The discussion centers on applying Gauss's Law to analyze the electric field around a hollow metallic sphere with an inner radius r1 and outer radius r2, containing a point charge Q located at a distance d less than r1 from the center. The electric field is zero within the conductive shell, while outside the shell, the electric field is determined using the formula E = Q/(4πr²ε₀). The participants confirm the correctness of this approach, emphasizing the role of induced charge on the conducting sphere in creating an external electric field.

PREREQUISITES
  • Understanding of Gauss's Law and its mathematical formulation
  • Familiarity with electric fields and their behavior in conductive materials
  • Knowledge of spherical symmetry in electrostatics
  • Basic concepts of charge induction in conductors
NEXT STEPS
  • Study the implications of Gauss's Law in different geometries, such as cylindrical and planar symmetries
  • Explore the concept of electric field lines and their significance in electrostatics
  • Investigate the behavior of electric fields in dielectrics versus conductors
  • Learn about the applications of Gauss's Law in solving complex electrostatic problems
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Physics students, electrical engineers, and anyone studying electrostatics or working with conductive materials in electrical applications.

Lancelot59
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You are a hollow metallic sphere of inner radius r1, and outer radius r2. Inside is a charge of magnitude Q and a distance d<r1 from the centre.

First I need to draw the electric field lines for regions r<r1, r1<r<r2, and r2<r

Since the sphere is a conductor the only place where there is not an electric field is inside the shell. The point charge induces a charge on the conducting sphere, making it in turn create an electric field outside the sphere.

I then need to use Gauss's law to find the electric field where possible. I think this is correct:

\int \vec{E}\cdot d\vec{A}=\frac{Q_{enclosed}}{\epsilon_{0}}
E\int d\vec{A}=\frac{Q}{\epsilon_{0}}
E(4\pi r^{2})=\frac{Q}{\epsilon_{0}}
E=\frac{Q}{4\pi r^{2}\epsilon_{0}}

For all locations that are not inside the shell. Am I correct?
 
Last edited:
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Looks fine to me.
 
Thanks for the confirmation.
 

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