Gaussian Optics / Paraxial Approximation

Click For Summary
SUMMARY

The discussion focuses on deriving the Gaussian optics formula \(\frac{n_1}{s_o} + \frac{n_2}{s_i} = \frac{n_2-n_1}{R}\) from the equation \(\frac{n_1}{l_o} + \frac{n_2}{l_i} = \frac{1}{R} \left( \frac{n_2s_i}{l_i} - \frac{n_1 s_o}{l_o} \right)\) using the paraxial approximation. Participants highlight the approximations for \(l_o\) and \(l_i\) and discuss the implications of the paraxial approximation where \(s_i \gg R\). The conversation reveals confusion regarding the expected results and the correct application of the formulas, particularly in the context of the signs and terms involved in the derivation.

PREREQUISITES
  • Understanding of Gaussian optics principles
  • Familiarity with the paraxial approximation in optics
  • Knowledge of the lens maker's equation
  • Basic calculus, specifically Taylor series expansion
NEXT STEPS
  • Study the derivation of the lens maker's equation in detail
  • Learn about the applications of the paraxial approximation in optical systems
  • Explore the implications of sign conventions in optical formulas
  • Investigate advanced topics in Gaussian beam propagation
USEFUL FOR

Optics students, physicists, and engineers working with optical systems who need to understand Gaussian optics and the paraxial approximation for practical applications.

DivGradCurl
Messages
364
Reaction score
0
Derive

\frac{n_1}{s_o} + \frac{n_2}{s_i} = \frac{n_2-n_1}{R}

for Gaussian optics from the following equation

\frac{n_1}{l_o} + \frac{n_2}{l_i} = \frac{1}{R} \left( \frac{n_2s_i}{l_i} - \frac{n_1 s_o}{l_o} \right)

by approximating

l_o = \sqrt{R^2 + \left( s_o + R \right) ^2 - 2R\left( s_o + R \right) \cos \phi}

and

l_i = \sqrt{R^2 + \left( s_i - R \right) ^2 - 2R\left( s_i - R \right) \cos \phi}

with the aid of

\cos \phi \approx 1

\hline

Here is what I have:

l_o \approx \sqrt{R^2 + \left( s_o + R \right) ^2 - 2R\left( s_o + R \right) } = \sqrt{R^2 + s_o ^2 + R^2 + 2s_o R - 2s_o R - 2R^2 } = s_o

and

l_i \approx \sqrt{R^2 + \left( s_i - R \right) ^2 - 2R\left( s_i - R \right) } = \sqrt{R^2 + s_i ^2 + R^2 -2s_i R - 2Rs_i + 2R^2} = 2R-s_i

But, I expected to find l_i \approx s_i ... what I have doesn't seem to work out. I can't find where I made a mistake, though.

Thanks
 
Last edited:
Physics news on Phys.org
Well keep in mind that the li and l0 are in the denominator...

You need to use the fact that \frac{1}{2R(1-\frac{s_i}{2R})} = \frac{1}{2R}(1 + \frac{s_i}{2R} +...)

Because of the paraxial approximation you have that si >>> R


regards
marlon : ps are you sure about these formulas ? Shouldn't there be a minus sign in the left hand side of your first given formula...
 
Last edited:
I've double checked my equations. Unfortunately, they're exactly equal to those in my calc book (Calculus: Concepts and Contexts 2nd Ed. by James Stewart - page 632). Well, I did some more work, but couldn't get the desired result. Anyway, here you go:

If

\frac{n_1}{s_o} = \frac{n_1}{l_o}

and

\frac{n_2}{s_i} = \frac{n_2}{2R-s_i} = \frac{n_2}{2R\left( 1 - \frac{s_i}{2R} \right)} = \frac{n_2}{2R} \sum _{n=0} ^{\infty} \left( \frac{s_i}{2R} \right)^n \approx \frac{n_2}{2R}

Then

\frac{n_1}{s_o} + \frac{n_2}{s_i} = \frac{n_1}{l_o} + \frac{n_2}{2R} = \frac{2Rn_1 + s_o n_2}{2Rs_o} = \frac{1}{R}\left( \frac{Rn_1}{s_o} + \frac{n_2}{2} \right) \neq \frac{n_2 - n_1}{R}

In other words, I'm stuck! :smile:
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
Replies
3
Views
609
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
2
Views
2K
Replies
6
Views
3K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K