Undergrad Gaussian Quadrature on a Repeated Integral

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Evaluating a repeated integral using Gaussian Quadrature can be challenging due to potential ambiguities in variable representation. The use of the same symbol for both integration variables and the integrand can lead to confusion, necessitating distinct symbols for clarity. Additionally, the integral may exhibit singular behavior based on specific parameter values. It is recommended to decompose the repeated integral into at least two simpler integrals with different limits for effective numerical integration. Properly addressing these issues will facilitate the application of Gaussian Quadrature.
olukelliot
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upload_2017-11-28_18-6-45.png

Hi there,
I am having some difficulty evaluating a repeated integral, which is the first of two shown in the image.
I had hoped to be able to use Gaussian Quadrature to provide a numerical result, however am unsure on if this is possible for a repeated integral?

I have attempted to use Cauchy' formula on repeated integrals to obtain a single integral, which is shown on the bottom in the image. However I am once again unsure on performing this due to the presence of φ.

Any ideas on what I'm doing wrong/ missing?
Thanks
 

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Your first integral is too ambiguous. You use φ for both integrations as well as as a variable in the integrand. You need to use two different symbols for the differential variables, so there would be no ambiguity for the variable in the integrand.
 
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Additionally, it seems like the integral could be singular, depending on the values of ##r_1##, ##m## and ##l##. It is not clear from your thread what the values of these quantities are.
 
You have to split the repeated integral into min. two simple integrals (with different borders) and each of them could be numerical integrated by Gauss.
See:
COMPUTATION OF DEFINITE INTEGRAL OVER REPEATED INTEGRAL Katar´ina Tvrda´, Maria Minarova´
Tatra mountains matematical publications
 
Relativistic Momentum, Mass, and Energy Momentum and mass (...), the classic equations for conserving momentum and energy are not adequate for the analysis of high-speed collisions. (...) The momentum of a particle moving with velocity ##v## is given by $$p=\cfrac{mv}{\sqrt{1-(v^2/c^2)}}\qquad{R-10}$$ ENERGY In relativistic mechanics, as in classic mechanics, the net force on a particle is equal to the time rate of change of the momentum of the particle. Considering one-dimensional...

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