Does Distance Affect the Electric Field Strength Above a Charged Plate?

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SUMMARY

The discussion centers on the effect of distance on the electric field strength above a charged plate. It is established that for an infinite sheet of charge, the electric field remains constant regardless of distance, as indicated by the principle that E-field lines are perpendicular to the plate. The confusion arises from the application of the point charge formula E = kq/r, which is not applicable in this scenario. For finite sheets of charge, distance does matter, but only when the observer is far enough away from the sheet.

PREREQUISITES
  • Understanding of electric fields and their properties
  • Familiarity with Gauss's Law
  • Knowledge of point charge versus infinite sheet charge configurations
  • Basic mathematical skills for manipulating equations like E = kq/r
NEXT STEPS
  • Study Gauss's Law and its applications to electric fields
  • Learn about the differences between electric fields from point charges and infinite sheets of charge
  • Explore the concept of electric field lines and their significance
  • Investigate the behavior of electric fields from finite sheets of charge at various distances
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Students of physics, electrical engineers, and anyone interested in understanding the principles of electric fields and their behavior in relation to charged plates.

oh.rry21
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So I'm trying to understand a couple things regarding this.

lets say we have a plate that's charged to Q. and we want to find the E field of a point .1 meters above the plate. when i looked at the solution, it never took the .1 meters into account when calculating the strength of the E field.

my roommate says that E field should be the same and thus the distance was irrelevant. so whether it was .1 meters or 1 meter above the plate, the E field would be the same.

but that doesn't make sense to me when you think about the equation for an electric field E= kq/r.

can anyone resolve that contradiction for me? :(
 
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oh.rry21 said:
my roommate says that E field should be the same and thus the distance was irrelevant. so whether it was .1 meters or 1 meter above the plate, the E field would be the same.
He's right, at least if you're talking about the field from an infinite sheet of charge. Or a finite sheet of charge at distances much smaller than the dimensions of the sheet. Of course, if the sheet of charge is only 10 cm square, the field 10 m away certainly will depend on distance.
but that doesn't make sense to me when you think about the equation for an electric field E= kq/r.
That's the field from a point charge--a very different configuration from an infinite sheet of charge. (Of course, as you get far enough away from a finite sheet of charge the field begins to look more and more like the field from a point charge.)

You might want to browse through this site: http://hyperphysics.phy-astr.gsu.edu/Hbase/electric/gaulaw.html#c4"
 
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Yep, because the e-field lines will be 100% perpendicular to the charged (supposedly infinitely wide) plate.
i.e. going straight up or straight down, so if you bound a gaussian cylinder above and through the plate, the field will go through only the circular discs at the end of the cylinder (and not the 'side walls' of the cylinder) - so it doesn't matter how high the cylinder is (drawing a picture would help heaps)
 

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