Gauss's Law - electric flux through a spherical shell

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SUMMARY

The discussion focuses on applying Gauss's Law to determine the electric flux through a spherical shell with a radius of 4 meters in a uniform electric field of 7020 N/C. The initial calculation attempted by the user, using the formula E * 4πr², resulted in an incorrect value of 1411454.747 N·m²/C. The key takeaway is that Gauss's Law states that if there is no charge enclosed within the shell, the total electric flux through the shell is zero, regardless of the external electric field.

PREREQUISITES
  • Understanding of Gauss's Law
  • Familiarity with electric fields and flux concepts
  • Basic knowledge of spherical geometry
  • Ability to perform calculations involving π and exponents
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  • Review the principles of Gauss's Law in electrostatics
  • Study the concept of electric flux and its mathematical representation
  • Explore examples of electric fields generated by various charge distributions
  • Learn about the implications of charge enclosed in Gaussian surfaces
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This discussion is beneficial for physics students, educators, and anyone studying electrostatics, particularly those looking to deepen their understanding of Gauss's Law and electric flux calculations.

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Homework Statement



A spherical shell of radius 4 m is placed in a uniform electric field with magnitude
7020 N/C. Determine the total electric flux through
the shell. Answer in units of N · m^2/C.

Homework Equations



Gauss's Law

The Attempt at a Solution



I thought this would be as simple as E * 4[tex]\pi[/tex]r[tex]^{2}[/tex] , but it's not working

I did 7020 * 4[tex]\pi[/tex]*4[tex]^{2}[/tex] and got 1411454.747, which isn't right. Is there something more to the problem that I'm missing?
 
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Is there any charge enclosed inside the shell? If there is no charge inside the shell, and the only electric field of concern is caused by some sort of charge distribution outside the shell, what does Gauss' law say about that?
 

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