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CuicCuic
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Hello physics world,
I am having a hard time understanding a rather simple thing. Let's consider the electric field produced by a uniformly charged ring of radius R, at a position $z$ along the ring's axis. From Coulomb's law in every textbook, we know that E_z∝Qz/(R^2+z^2). That is, there is a net field produced by the ring along its axis.
Now, if we consider the same problem with Gauss's law, I run into a conceptual problem. Let's say we take a Gaussian sphere with radius r, smaller than R, whose center is placed at the center of the ring. In that case, there is no charge enclosed within the Gaussian surface. So Gauss's law should say that the electric field must be zero. But we know that the electric field is finite along $z$ and does not cancel out from $z$ and $-z$. Instead it seems to me that the flux would be 2E_z.
There must be something wrong with my understanding of Gauss's Law, because as I understand it, if there is not charge inside the Gaussian sphere, the electric field flux through that sphere is 0. Any help clarifying this would be sincerely appreciated.
(I know that using Gauss's law for this problem is not a good idea because the field will not be constant in the surface integral. My question is thus rather conceptual.)
I am having a hard time understanding a rather simple thing. Let's consider the electric field produced by a uniformly charged ring of radius R, at a position $z$ along the ring's axis. From Coulomb's law in every textbook, we know that E_z∝Qz/(R^2+z^2). That is, there is a net field produced by the ring along its axis.
Now, if we consider the same problem with Gauss's law, I run into a conceptual problem. Let's say we take a Gaussian sphere with radius r, smaller than R, whose center is placed at the center of the ring. In that case, there is no charge enclosed within the Gaussian surface. So Gauss's law should say that the electric field must be zero. But we know that the electric field is finite along $z$ and does not cancel out from $z$ and $-z$. Instead it seems to me that the flux would be 2E_z.
There must be something wrong with my understanding of Gauss's Law, because as I understand it, if there is not charge inside the Gaussian sphere, the electric field flux through that sphere is 0. Any help clarifying this would be sincerely appreciated.
(I know that using Gauss's law for this problem is not a good idea because the field will not be constant in the surface integral. My question is thus rather conceptual.)