- #1

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thanks

bigerst

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- Thread starter bigerst
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- #1

- 57

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thanks

bigerst

- #2

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∇.E=ρ/ε

E=-∇ψ-∂A/∂t, if you put it into above you get,

-∇

now using lorentz gauge(more preferable) we have ∇.A=-1/c

if you will put it into (1) you will get the the general form of potential equations.this proof starts with gauss law but the converse can also be done in order to arrive at gauss law.here it does not refer to any coulomb law,and so it is more general.

- #3

Meir Achuz

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on the four Maxwell equations. Applying the divergence theorem to Maxwell's div D equation gives Gauss's law. Coulomb is the electrostatic case.

- #4

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alright thanks :)

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