(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A closed surface with dimensions a = b = 0.400 m and c = 0.800 m is located as shown in the figure below. The left edge of the closed surface is located at position x = a. The electric field throughout the region is nonuniform and given by E = (2.70 + 2.20 x2)i N/C, where x is in meters.

https://www.webassign.net/serpse8/24-p-061.gif

A)Calculate the net electric flux leaving the closed surface.

2. Relevant equations

For a closed surface Integral of E(dot)dA = q_{enclosed}/Epsilon_{0}

3. The attempt at a solution

Obviously I will have to integrate the Electric field here. I began with the simple formula

Int(E dot dA) from 1.2 to 0 because the distance at the edge where the E field leaves is 1.2m out. I believe since the sides are all parallel to the E field those become 0.

So I tried integrating

2.70 + 2.20x^2 dA from 1.2 to 0

I believe dA is x^2 (a=b=x) and dA is the combined infinitesimal areas to produce LxW of the end of the box.

The angle between the exiting E field and the Normal to the plane at the end of the box are parallel thus negligible.

What's going wrong here :-/

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# Gauss's Law with NONuniform E field

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