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General Formula using Miscellaneous Substitution

  1. Nov 1, 2006 #1
    I'm really stomped with this problem... i can't seem to get the answer...

    anyway... here's the problem..

    (2(x^3) - (y^3))y'=3(x^2)y

    and i need to get the general solution....

    SO, here's what i did...

    I Let
    u=x^3 and

    so what happens is

    2udy-(y^3)dy= ydu

    and that's where i got stuck...

    i tried using

    but i can't seem to get rid of the 2 in 2udy and it would be much of a problem if i did that...

    could anyone help me??
  2. jcsd
  3. Nov 1, 2006 #2


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    Dearly Missed

    Rewrite this diff.eq as:

    I'm sure you have solved such problems previously.
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